(4) { 4 4 41 (5) 3 3 *OH YOL 61 4 = 41 M. R.5 at 5 M.R. 7 (2) = 4 answer 4 of each sort. 30 M.R. 36 48. 22 18 ]] 4 CASE 3. 71 4 at 7 EXAMPLES. 3 of water, answer. 4 Against the price of the 4 given quantity stands 48. 41 26+14+8=48 Therefore, As 48bu: 4bu. :: Izbu. : ibu. of each sort. Answer. 2 Against the given quantity stands 2, cono2 sequently the quantity for 16, 20 & o will be 10 oz. Then, as 2 oz.: 34 oz. :: 10 oz.: 170 oz. answer. 16 Against the price of the given quantity. bu. p. }} 16+4=20|Against the price, &c. bu. 6 (2) M. R. Sum of the difference=7 (4) M. R. (48) 33 Then, as 48: 80 :: 330155 8 48 gal. gal. S4 = 25 Sum 110 (3) Suppose 100÷ 20 Then, as 613: 74:: 100: 120 { /=163}\ answer. (4) Suppose 250l. whose interest for 10 yrs.150l. and 150l. +250l.=400l. Therefore, as 4,00l.: 5,00l. :: 2501. : 312%. 10s. answer. (5) Suppose 20 min. of an hour 20 min. of 2 hours 20 54)162 com. denominator. 27 18 Then, as IIparts: 20min. :: 18parts: 32min. 437 sec. ans. (6) Suppose 90%. (÷}=30 From 90 Thus; 90+4=224/ Take 67 ᄒᄒ=15 22/ 671/ Then, as 221. : 281. :: 901.: 1127. answer. (7) Suppose 45 and 45 X 3527 which x7-189 45X2÷3 30+ 219 Then, as 219: 292: 45: 60 years. answer (S) Suppose 100 33 25 20 Sum 78 (10) Suppose 80 Then, as 78: 100 :: 94: 120 answer. (9) Suppose 600, whose interest for 12 yrs. =432 and 600 +432=1032: Then, as 1032 600 :: 860: 500l. answer. 263 20 Then, as 76 : 80 :: 57 : 60 answer. 16 134 Sum 76 (11) Suppose 100 scholars 2 200 Sch. Sch. Sch. Sch. 50 Then, as 308: 333 :: ICO: 108 33 31 25 308 99900 925 108 ans. (12) Suppose 90%. Then 90÷30 & 90—30=60l. A lays out and 60 x 2120 B lays out; then 120-90 30 which should be 50. Therefore, as 3ol.: 50 :: gol. 150. answer. (13) Suppose 120,00% 1200,0 6 600 720,00 -600 Then, as 120l.: 100 :: 12000l.: 10000l. answer. £. 120 DOUBLE POSITION. EXAMPLES. (2) 1st. Sup. A had 15. 2d. Sup. A had 25%. Then, 15 X 2-8-22 B. then, 25 × 2-8-42 B. and 15X3-15=30C. and 25×3-15=60C. (Excels 127-100=27 20 10s. A's part 20 10X2- 8=33 O B's do. (3) 1st. sup. A paid 12 Then 12+10=22 B. and 12+2234 C. 2d. Sup. A paid 16 100-68-32 defect.. 100-84-16 defect. continued, Then, 70+2+20=55 B's then 90÷2+20-65 B'8 and 20 A's and 20 A's answer C's age 80 yrs. Take B & A's 80 remains o the Proof. (5) 1st. Sup. the body 30 inches. 2d. Sup. 40 inches. 21. 18. 8d.=500d. 200 300 Defect. 20X150-3000 Difference 15,0) 450,0 answer, he worked 30 days. 2nd. Suppose 25 days at work. Then 25 at 20d. = 500 and 15 idle at 10d.=150 500-350-150 defect. continued |