Electro-chemistry: General theoryLongmans, Green and Company, 1904 - 268 страници |
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... joules per mol ) . T = Absolute temperature . Ил Ис = Mobility of anion and cation ( see p . 43 ) . W = Work ( see p . 179 ) . A = Equivalent conductivity ( see p . 58 ) . dE d Ꭲ la lc = Temperature coefficient of electromotive force ...
... joules per mol ) . T = Absolute temperature . Ил Ис = Mobility of anion and cation ( see p . 43 ) . W = Work ( see p . 179 ) . A = Equivalent conductivity ( see p . 58 ) . dE d Ꭲ la lc = Temperature coefficient of electromotive force ...
Страница 153
... joule . Hence the definition , " The electromotive force between two points is one volt when the work done in transferring a coulomb from one point to the other is a joule ; " or , briefly , volt = joule coulomb But as working at the ...
... joule . Hence the definition , " The electromotive force between two points is one volt when the work done in transferring a coulomb from one point to the other is a joule ; " or , briefly , volt = joule coulomb But as working at the ...
Страница 154
... joules i.e. when zinc replaces copper in a solution of the sulphate containing 100 mols of water to one of salt , the evolution of heat amounts to 209,910 joules for every 65 grams of zinc dissolved . Hence the heat of reaction is the ...
... joules i.e. when zinc replaces copper in a solution of the sulphate containing 100 mols of water to one of salt , the evolution of heat amounts to 209,910 joules for every 65 grams of zinc dissolved . Hence the heat of reaction is the ...
Страница 155
... joules of chemical energy are spent when two equiva- lents of zinc dissolve . But two equivalents of zinc carry with them two faradays of electricity ; hence to get the voltage we must divide 209.910 by this quantity expressed in ...
... joules of chemical energy are spent when two equiva- lents of zinc dissolve . But two equivalents of zinc carry with them two faradays of electricity ; hence to get the voltage we must divide 209.910 by this quantity expressed in ...
Страница 156
... joules according to these two observers respectively . Since in the reaction two faradays are involved , we may , taking the mean of the two numbers , calculate the E.M.F. as = 364,000 joules ( 2 x 96600 ) coulombs 1.88 volts Experiment ...
... joules according to these two observers respectively . Since in the reaction two faradays are involved , we may , taking the mean of the two numbers , calculate the E.M.F. as = 364,000 joules ( 2 x 96600 ) coulombs 1.88 volts Experiment ...
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according accumulator acetic action amount ampere anion anode aqueous atom B.Sc cadmium calculated carboxyl groups cathode cations cent centimetre Chem chemical CHEMISTRY chlorine Clark cell coils College complex ions compounds concentration constant containing copper coulombs Crown 8vo cubic centimetre current density D.Sc Daniell cell deposited Diagrams dilute solutions discharge dissociation dissolved effect electro-affinity electrode potential electromotive force ELEMENTARY Engineering equation equiv equivalent conductivity faraday free energy gases give gram-equivalent Hence hydrogen ions hydroxyl Illustrations ionic ionisation ionisation-constant joules K₁ Kohlrausch latent heat law of dilution liquid litres measured mercury metal migration ratio mobility molecules normal ohms Ostwald oxygen phys Plates platinum polarisation positive potential difference PRACTICAL Professor quantity of electricity resistance Royal 8vo salts saturated silver sodium substance substitution succinic acid sulphate sulphuric acid theory tion tube velocity voltage voltameter volts wire zinc ΙΟ
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