 | James Gallier - 1836 - 228 страници
...232634 386 279694 435 -327SS2 AREAS OP THE SEGMENTS OF A CIRCLE. USE OF THE TABLE. PROBLEM. Toßnd the Area of a Segment of a Circle. RULE. — Divide...or versed sine, by the diameter of the circle, and find the quotient in the column of versed sines, or heights. Then take out the corresponding area,... | |
 | John Bonnycastle - 1842 - 318 страници
...whose radius is 13. Ans. 265.4652. 4. Required the area of a quadrant whose radius is 21. Ans. 346.3614 PROBLEM To find the area of a segment of a circle. RULE I.* 1. Find the area of the sector, having the same arc with the segment, by the last problem. 2. Find... | |
 | Charles Haynes Haswell - 1844 - 298 страници
....327 .271 .17197 .326 .22227 .381 . 27483 .436 .325 r, TABLE — (Continued). USE OF THE ABOVE TABLE. To find the Area of a Segment of a Circle. RULE.—...or versed sine by the diameter of the circle, and find the quotient in the column of versed sines. Take the area noted in the next column, and multiply... | |
 | J. A. Powers - 1845 - 84 страници
...stands ... - 4.714 Under 6 stands - - - - 2.8284 Sum = the answer = - - - 101.8224 TABLE XV. To Jind the Area of a Segment of a Circle. RULE. — Divide the height or versed sine by the diameter, and seek lor the quotient >i the column of versed sines headed height. Take out also the corresponding... | |
 | Thomas Tate (mathematical master.) - 1848 - 284 страници
...A/3 = 23-38. 5. Required the area of a regular octagon, whose side is 8ft. Ans. 309-019 sq.ft. 1-4. PROBLEM. To find the area of a segment of a circle. RULE. Find the area of the sector A c BE ; also find the area of the triangle ABE ; then the difference of... | |
 | J. M. Scribner - 1849 - 286 страници
...-27872 -434 -32689 -239 -14409 .288 -18723 -337 -23263 -386 -27969 -435 32788 USE OF THE ABOVE TABLE. To find the Area of a Segment of a Circle. Rule. —...or versed sine, by the diameter of the circle, and find the quotient in the column of versed sines. Then take out the corresponding area, in the next... | |
 | Charles Haynes Haswell - 1851 - 346 страници
....22134 .380 .27386 .435 .32' .271 .17197 .326 .22227 .381 .27483 .436 .:\-:• G USE OF THE ABOVE TABLE. To find the Area of a Segment of a Circle, RULE. —...or versed sine by the diameter of the circle, and find the quotient in the column of versed sines. Take the area noted in the next column, and multiply... | |
 | Oliver Byrne - 1851 - 310 страници
...-487 -488 -489 -490 / -378701 -379700 -380700 -381699 -382699 -390500 -390730 -390953 -391166 -391370 To find the area of a segment of a circle. RULE. —...or versed sine, by the diameter of the circle, and find the quotient in the column of heights. 6S PROPORTIONS OF THE LENGTHS OF CIRCULAR ARCS. Hcight... | |
 | Septimus Norris - 1852 - 356 страници
...-385490 -430 -322928 -368531 li -470 -362717 -385834 To find the Area, of the Segment of a CircleRULE — Divide the height, or versed sine, by the diameter of the circle, and find the quotient in the column of heightsThen take out the corresponding area, in the column of areas,... | |
 | Septimus Norris - 1854 - 334 страници
...-358725 -359723 -360721 -361719 -362717 -384426 -384786 -385144 -385490 -385834 To find the Area of the Segment of a Circle. RULE. — Divide the height, or versed sine, by the diameter of the circle, and find the quotient in the column of heights. Then take out the corresponding area, in the column of... | |
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To find the area of a segment of a circle. Rule. — Divide the height, or versed sine, by the diameter of the circle, and find the quotient in the column of versed sines. 
